Mechanical

Flywheel Energy Calculator

Calculate flywheel stored energy, usable energy between speeds, moment of inertia, angular velocity, rim speed, and Wh equivalent.

Formula E = 1/2 I omega^2Reviewed Sep 1, 2026

A flywheel stores energy as rotational kinetic energy: E = 1/2 I omega^2. This calculator estimates energy from mass, radius, RPM, and a selected inertia model, then adds the practical checks users usually need next: moment of inertia, angular speed, rim speed, energy per mass, watt-hour equivalent, and the usable energy released when the flywheel slows from one RPM to another.

Calculation Bench
Solve for
Inertia Model
01

m · total rotating mass for this inertia model

02

R · outer radius, not diameter

03

n1 · operating speed before conversion to rad/s

Use radius, not diameter. If your CAD model gives mass moment of inertia directly, choose Custom I.

Solution

Enter flywheel geometry and RPM to calculate stored rotational energy.

E = 1/2 Iω²

Formula Sheet

E=12Iω2E=\dfrac{1}{2}I\omega^2
ΔE=12I(ω12−ω22)\Delta E=\dfrac{1}{2}I(\omega_1^2-\omega_2^2)
ω=2πn60\omega=\dfrac{2\pi n}{60}
I=12mR2I=\dfrac{1}{2}mR^2
I=12m(Ro2+Ri2)I=\dfrac{1}{2}m(R_o^2+R_i^2)
I=mR2I=mR^2
v=ωRv=\omega R
  • EStored Energy
  • Delta EUsable Energy
  • IMoment of Inertia
  • mMass
  • ROuter Radius
  • RoOuter Ring Radius
  • RiInner Ring Radius
  • nRotational Speed
  • omegaAngular Speed
  • vRim Speed

Flywheel Inertia Model Guide

ModelMoment of inertiaUse when
Solid diskI = 1/2 mR²Mass is spread through a uniform circular disk
Thick ringI = 1/2 m(Ro² + Ri²)Flywheel has a bore or annular rim section
Thin rimI = mR²Most mass is concentrated near the outer radius
Custom II entered directlyCAD, test data, or a datasheet gives kg·m²

Variables & Units

SymbolVariableDescriptionCommon Units
EStored EnergyRotational kinetic energy at the entered speed.J, kJ, Wh, ft·lbf
Delta EUsable EnergyEnergy released between the initial and final speeds.J, kJ, Wh
IMoment of InertiaMass moment of inertia about the spin axis, in kg·m².
mMassTotal rotating mass represented by the selected inertia model.kg, lb
ROuter RadiusOuter radius used for solid disk or thin-rim inertia and rim speed.mm, m, in
RoOuter Ring RadiusOuter radius for thick-ring inertia.mm, m, in
RiInner Ring RadiusBore or inner radius for thick-ring inertia.mm, m, in
nRotational SpeedFlywheel speed before conversion to rad/s.rpm, rad/s
omegaAngular SpeedRotational speed in radians per second.
vRim SpeedOuter surface speed, useful as a quick stress-screening signal.m/s, ft/min

How to Use This Calculator

  • 01Choose Stored Energy when you want total energy at one operating speed.
  • 02Choose Usable Speed Drop when you want the energy released between an initial RPM and a lower final RPM.
  • 03Pick the inertia model that best matches the mass distribution: solid disk, thick ring, thin rim, or custom moment of inertia.
  • 04Enter mass and outer radius for geometry-based models; thick-ring mode also needs inner radius.
  • 05Read energy in kJ and Wh, then check rim speed. High rim speed is often the first warning that stress, containment, balancing, and bearing design need specialist review.

How the Formula Works

RPM is converted to angular speed with omega = 2 pi n / 60 before the energy equation is applied.

For a solid disk, I = 1/2 mR^2. For a thick ring, I = 1/2 m(Ro^2 + Ri^2). For a thin rim, I = mR^2. A rim-heavy flywheel stores more energy than a solid disk of the same mass and outer radius.

Stored energy scales with speed squared. Doubling RPM quadruples energy if the moment of inertia stays the same.

In speed-drop mode, usable energy is the difference between the high-speed and low-speed stored energies: Delta E = 1/2 I(omega1^2 - omega2^2).

Rim speed is v = omega R. It is not a full stress calculation, but it is a useful sanity-check output because flywheel stress also rises strongly with speed.

Worked Example 01

10 kg solid disk at 3000 rpm

Known

  • Mass: 10 kg
  • Outer radius: 0.2 m
  • Speed: 3000 rpm

Formula

E = 1/2 I omega^2

Substitution

I = 1/2 x 10 x 0.2^2 = 0.2 kg·m²; omega = 2pi x 3000 / 60 = 314.16 rad/s; E = 1/2 x 0.2 x 314.16^2

Result

E ≈ 9.87 kJ, or about 2.74 Wh

This matches the standard solid-disk example. The rim speed is about 62.8 m/s, so stress and containment should be reviewed before treating this as a safe hardware design.

Worked Example 02

Usable energy from 3000 rpm down to 2500 rpm

Known

  • Mass: 50 kg
  • Outer radius: 0.3 m
  • Initial speed: 3000 rpm
  • Final speed: 2500 rpm

Formula

Delta E = 1/2 I (omega1^2 - omega2^2)

Substitution

I = 1/2 x 50 x 0.3^2 = 2.25 kg·m²; Delta E = 1/2 x 2.25 x (314.16^2 - 261.80^2)

Result

Delta E ≈ 33.9 kJ, or about 9.42 Wh

The flywheel still contains energy at 2500 rpm. Only the difference between the two stored-energy levels is usable over that allowed speed drop.

Applications

  • 01Estimating stored energy in an engine, press, generator, or test rig flywheel
  • 02Comparing solid disk, thick ring, and rim-heavy flywheel concepts
  • 03Estimating usable energy when speed is allowed to droop between two RPM limits
  • 04Converting flywheel energy to Wh for comparison with electrical storage
  • 05Screening rim speed before moving to stress and burst-speed analysis

Assumptions

  • 01The flywheel is a rigid body spinning about its central axis.
  • 02Mass distribution is approximated by the selected inertia model.
  • 03Speed is steady for stored-energy mode; speed-drop mode uses the difference between two steady speeds.
  • 04Rim speed is a screening signal only, not a substitute for a rotating-disk stress or burst-speed calculation.

Where This Model Stops

  • 01Does not calculate hoop stress, radial stress, burst speed, containment energy, fatigue, balance grade, bearing losses, windage, gyroscopic loading, or shaft stresses.
  • 02Does not account for spokes, hubs, nonuniform density, composite layups, shrink fits, cracks, keyways, bolt holes, or temperature effects.
  • 03High-speed flywheels can be dangerous stored-energy devices. Use qualified engineering review, material allowables, containment, and applicable standards before building hardware.
  • 04Custom inertia mode assumes the entered I value already represents the complete rotating assembly about the correct axis.

References

  1. [1]
    Flywheels - Kinetic Energy

    Engineering ToolBox

    Reference for E = 1/2 I omega^2, angular velocity conversion, and inertia shape factors.

  2. [2]
    Flywheel Energy & Burst-Speed Calculator

    Eng Bench

    Reference for stored energy, thick-ring inertia, rim speed, and the importance of stress/burst-speed checks.

  3. [3]
    Flywheel Energy Calculator

    MachineCalcs

    Reference for calculator UX: solid disk, thick ring, thin rim, moment of inertia, rim speed, and angular speed outputs.

Frequently Asked Questions

What is the flywheel energy formula?

Flywheel energy is E = 1/2 I omega^2, where I is moment of inertia and omega is angular speed in rad/s. RPM must be converted with omega = 2 pi n / 60.

Why does RPM matter so much?

Energy is proportional to omega squared. If the flywheel geometry and mass stay the same, doubling RPM stores four times as much energy.

Which inertia model should I choose?

Use solid disk for a uniform disk, thick ring for an annular flywheel with a significant bore, thin rim when most mass is concentrated near the outside radius, and custom inertia when a CAD model or datasheet gives I directly.

How is this different from the Kinetic Energy Calculator?

The Kinetic Energy Calculator handles straight-line motion with KE = 1/2 mv^2. This calculator handles rotating bodies, so it needs moment of inertia and angular velocity.

Can rim speed tell me if a flywheel is safe?

No. Rim speed is only an early warning signal. Safe flywheel design needs material stress, burst-speed, fatigue, balancing, containment, and bearing checks.