Electrical
13 Electrical Engineering Formulas Explained (Ohm's Law to Power Factor)
By Saurabh
Electrical engineering runs on a compact set of relationships that recombine constantly - DC circuit basics, the AC power triangle, and a handful of practical conversions between watts, amps, and billed energy. These thirteen cover the ones that show up most, from Ohm's Law to power factor. Every one links to a calculator that runs the numbers with proper units, so you can check your own work against a real example.
Ohm's Law: V = IR
A multimeter measures voltage and resistance directly but usually can't measure current without breaking the circuit open to insert it in series - which is why Ohm's Law works as much as a diagnostic shortcut as a design formula: measuring V and R at a suspect connection and computing I is often faster and safer than rewiring a live circuit just to read current directly.
The relationship only holds this simply for ohmic materials, where resistance stays constant regardless of the voltage applied. A component that doesn't behave this way still obeys the same underlying physics, but a single V/I measurement at one operating point won't predict its behavior at a different one the way it reliably does for a plain resistor.
Try the Ohm's Law Calculator.
Series Resistance: Rtotal = R1 + R2 + R3 + ...
A string of old-style series-wired holiday lights demonstrates the practical downside of series wiring better than any circuit diagram: because current has exactly one path through every bulb, one burned-out filament breaks continuity for the entire string, which is why modern LED strings are wired in parallel instead - one failed segment doesn't take the whole run down with it.
That single-path property is also what makes series resistance simple to reason about: there's no current-splitting to account for, so whatever current flows through the first resistor is exactly what flows through every other one in the chain, and the total opposition is just their sum.
Parallel Resistance: 1/Rtotal = 1/R1 + 1/R2 + 1/R3 + ...
Household electrical outlets are wired in parallel for the opposite reason a series string fails: every outlet needs the same full supply voltage available independently, and one device failing or being unplugged shouldn't cut power to everything else sharing that circuit - the same multiple-path property that lowers total resistance is also what keeps each branch electrically independent of the others.
This is also the formula people most often get backwards on first exposure - instinctively expecting more resistors on a circuit to mean more total resistance, when adding another parallel path does the opposite, pulling the equivalent resistance below even the smallest individual resistor in the group.
Voltage Divider: Vout = Vin × R2 / (R1 + R2)
A voltage divider is one of the most common ways to bias a transistor or reference a sensor input, but it comes with a real tradeoff: current constantly flows through R1 and R2 even when nothing is connected to the output, so low resistor values (which resist voltage sag better once a real load is attached) directly cost more standby power dissipated in the divider itself.
Picking divider values is usually a balance between those two competing pressures - a low-power design pushes toward higher resistor values, while a design that needs to actually drive something meaningful off the output pushes toward lower ones, and the ratio alone (which sets the voltage) doesn't settle that question either way.
Try the Voltage Divider Calculator.
Electrical Power: P = VI (also P = I²R and P = V²/R)
Power has three equivalent forms because Ohm's law connects V, I, and R, so substituting that relationship into P = VI eliminates whichever variable you don't happen to know, leaving three algebraically identical ways to reach the same number.
In practice, the I²R form is what actually matters for why a wire or fuse heats up: power dissipated as heat scales with the square of current, not linearly with it, which is why a modest overcurrent - say, 20% over rating - produces noticeably more than 20% more heating, and why fuse and breaker ratings have so little margin before they trip.
Try the Electrical Power Calculator.
Voltage Drop: Vdrop = 2 × I × ρ × L / A
Resistivity (ρ) isn't quite constant - copper and aluminum both get modestly more resistive as they heat up, so a voltage-drop calculation using a standard room-temperature resistivity value slightly underestimates the actual drop in a conductor running hot inside a wall, attic, or crowded conduit on a fully loaded circuit.
For most everyday residential circuits that temperature effect is small enough to ignore safely, but it's part of why some engineering references derate ampacity and voltage-drop together for conductors expected to run hot, rather than treating heating and voltage drop as two fully independent checks.
Try the Voltage Drop Calculator.
Single-Phase Power: P = V × I × PF
A motor nameplate is often the clearest place to see this triangle matter in practice: two motors can be rated for the identical real horsepower output, but if one has a lower power factor than the other, it draws more current for that same useful work and needs larger supply conductors and a bigger breaker to deliver it.
That extra current isn't doing anything productive - it's apparent power the system still has to carry even though it isn't converted into motion, heat, or light, which is exactly the gap real power, reactive power, and apparent power are each named to describe separately.
Try the Single-Phase Power Calculator.
Three-Phase Power: P = √3 × VL × IL × PF
Three-phase distribution needs less conductor material to deliver the same power as single-phase at a comparable voltage and current rating, one practical reason utilities and industrial facilities standardize on it for anything beyond small residential loads.
It also delivers noticeably smoother torque to a motor than single-phase does - a single-phase supply's power pulses twice per AC cycle, while three balanced phases overlap those pulses enough that the combined power delivered to the load stays essentially constant, which is part of why three-phase motors run with less vibration for a given size.
Try the Three-Phase Power Calculator.
Power Factor: PF = P / S
Power factor can be either lagging (an inductive load like a motor, where current trails voltage) or leading (a capacitive load, where current leads voltage). Correction deliberately adds capacitance to introduce just enough leading reactive power to cancel out an inductive load's lagging reactive power.
That's why a correction calculation is a subtraction between two phase angles rather than a flat percentage adjustment - the capacitor bank only has to supply the reactive-power gap between where the facility's power factor currently sits and where it needs to land, not replace any of the real power being consumed.
Try the Power Factor Calculator.
Capacitor Energy: U = ½CV²
This squared-voltage relationship is why capacitor banks built for energy storage or pulsed-power use are rated primarily by their maximum voltage rather than by capacitance alone - exceeding that rating even briefly risks dielectric breakdown, and because stored energy scales with the square of voltage, a modest overvoltage pushes both the stored energy and the failure risk up disproportionately fast.
It's also why a charged capacitor can stay dangerous well after a circuit is switched off: the energy stored this way doesn't dissipate just because the power source is disconnected, which is exactly why deliberately discharging a large capacitor bank before working on equipment is a genuine safety practice, not a formality.
Try the Capacitor Energy Calculator.
Battery Life: t = C / I
A common mistake feeding this formula is mixing up units: battery capacity is usually rated in mAh (milliamp-hours) while current draw is often measured directly in amps, and forgetting to convert between the two before dividing produces an answer that's off by a factor of 1,000, not a small rounding error.
Run the same relationship in reverse and it becomes a design tool rather than a runtime check: given a target runtime and a known current draw, solving for capacity tells you the minimum battery size to buy - often the more useful direction to run this formula in during actual product design than starting from a battery you've already picked.
Try the Battery Life Calculator.
Watts to Amps: I = P / V (DC); I = P / (V × PF) (AC)
This is the formula behind a common practical question: an appliance's nameplate lists wattage, but breakers and wire gauge are rated in amps, so converting the nameplate wattage into actual current draw is the necessary first step before checking whether an existing circuit can safely handle a new appliance.
Skip the power factor term on an AC load that has any real inductance or capacitance, and the calculated current comes out too low - an easy mistake when copying a DC-style calculation over to a motor or another reactive AC load without adjusting the formula to match.
Try the Watts to Amps Calculator.
kWh: Energy = Power × Hours / 1,000
Utilities bill in kilowatt-hours rather than watts because kWh captures total energy consumed over a period, while watts is only a snapshot of demand at one instant - a modest space heater left running all afternoon can easily consume more total energy than a much higher-wattage appliance that's only switched on for a few minutes, which is exactly why wattage alone is a poor guide to actual running cost without also accounting for how long something runs.
Devices left plugged in but seemingly "off" - a phone charger, a game console in standby, a TV waiting for a remote signal - often draw a small but continuous trickle of power that adds up in kWh terms over a full month even though no single moment of that draw looks significant, which is why a home energy audit usually turns up more phantom-load kWh than most people expect.
Try the kWh Calculator.
Quick Reference - All 13 Formulas
| Formula | Expression | Primary Use |
|---|---|---|
| Ohm's Law | V = IR | Basic DC circuit analysis |
| Series Resistance | Rtotal = R1 + R2 + ... | Equivalent resistance, one current path |
| Parallel Resistance | 1/Rtotal = 1/R1 + 1/R2 + ... | Equivalent resistance, multiple current paths |
| Voltage Divider | Vout = Vin × R2 / (R1 + R2) | Scaling a voltage down for biasing or reference |
| Electrical Power | P = VI | Basic power calculation |
| Voltage Drop | Vdrop = 2IρL / A | Wire sizing for long conductor runs |
| Single-Phase Power | P = V × I × PF | Real/apparent/reactive power for AC loads |
| Three-Phase Power | P = √3 × VL × IL × PF | Motor and industrial power calculations |
| Power Factor | PF = P / S | Correction capacitor sizing |
| Capacitor Energy | U = ½CV² | Stored energy in a charged capacitor |
| Battery Life | t = C / I | Estimating device runtime |
| Watts to Amps | I = P / V | Sizing breakers and wire from a wattage rating |
| kWh | Energy = P × h / 1,000 | Utility billing and appliance running cost |
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Frequently Asked Questions
Why does this list cover both Series/Parallel Resistance and Voltage Divider separately?
A voltage divider is technically a series circuit, but the two formulas answer different questions: series/parallel resistance combines resistors into a single equivalent value, while a voltage divider uses that same series relationship specifically to produce a target output voltage from a larger input - a distinct enough use case that it's normally taught and looked up separately.
Is apparent power (S) ever the number that actually matters, or is real power (P) always what counts?
Apparent power is exactly what matters for sizing supply equipment - transformers, wiring, and breakers all have to be rated for the current the apparent power actually draws, even though only the real-power portion of that current does useful work. A utility's demand charges are often tied to apparent power (kVA) for this reason, not just the real energy (kWh) consumed.
Why do single-phase and three-phase power use different formulas for what seems like the same physical quantity?
They're measuring power delivered across a different number of conductors with a different phase relationship between them, so the multiplier changes - 1 for single-phase, √3 for three-phase measured line-to-line - but the underlying real-power concept (voltage times current times the cosine of the phase angle) is identical in both cases.
Does a fully charged capacitor and a fully charged battery store energy the same way?
No - a capacitor stores energy directly in an electric field (U = ½CV²) and can release nearly all of it almost instantly, while a battery stores energy in a chemical reaction and releases it gradually, limited by how fast that chemistry can proceed. That's why capacitors are used for fast pulses of power and batteries for sustained runtime, not interchangeably.
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